This question evaluates to:
a. p or q
b. r or s
c. p and t or !p and !t
d. s -> q
e. s or !t
f. s or u
g. v -> w
The question seems to come down to c, but there is no way to determine whether they are both true or false.
Because there needs to be at least one standalone proposition or a way to solve for it (for instance using specialization) ie: p and q therefore p or therefore q.
I declare this question to be ambiguous, too little data to make a logical assumption about it.
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That said if you assume both in c are true than the problem evaluates to:
s or !t (using elimination)
t therefore s = Bread is on the table.
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or
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If you assume both in c are false the problem evaluates to:
p and t
therefore p and t are true
p or q
p
therefore !q
s -> q
!q
therefore !s
s or u
!s
therefore u = its in turks ass